Physics/Lessons/Materials/Hooke's Law & the Young Modulus
Physics · Materials · AS Level

Hooke's Law & the Young Modulus

A thick steel wire and a thin steel wire stretch by different amounts under the same force, despite being the same material. Force and extension alone can't separate "how stiff is this sample" from "how stiff is this material" — stress and strain can, and the Young modulus is what falls out of that separation.

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Hooke's law

Stretch most solid materials by a small amount and the extension produced is directly proportional to the force applied. This is Hooke's law:

$F = k\,\Delta L$

where $F$ is the applied force, $\Delta L$ is the extension, and $k$ is the stiffness (or spring constant) of the sample, in newtons per metre (N m−1). A larger $k$ means more force is needed for the same extension.

Hooke's law holds up to the limit of proportionality: beyond it, the graph stops being a straight line. This is a separate point from the elastic limit, which comes slightly after — up to it, the material still returns fully to its original length once the force is removed, even where the graph is no longer straight. Only past the elastic limit does deformation become permanent.

Two different limits — don't conflate them

The limit of proportionality is where the force-extension graph stops being a straight line — $F$ and $\Delta L$ are no longer proportional beyond it. The elastic limit is a separate, slightly later point, beyond which deformation becomes permanent (plastic) rather than fully reversible. Between the two, a material can be non-linear — the graph curves — while still being fully elastic: remove the force anywhere before the elastic limit and the sample returns exactly to its original length, straight-line region or not.

Elastic behaviour

"Elastic" in physics specifically means the deformation is fully reversible. A material stretched within its elastic limit stores the work done on it as elastic strain energy, all recoverable once the force is removed.

Why force and extension aren't enough

$k$ describes a specific sample, not the material. Cut a wire in half and the shorter piece needs more force for the same extension — effectively stiffer, though it's the same material. A thicker wire of the same length is stiffer too. $k$ is tangled up with both length and cross-sectional area, making it useless for comparing materials.

What's needed is a way of describing deformation that strips out sample geometry, leaving only a property of the material. That's stress and strain.

Tensile stress

Tensile stress is the force applied per unit cross-sectional area:

$\sigma = \dfrac{F}{A}$

where $\sigma$ is stress, $F$ is the applied force, and $A$ is cross-sectional area. Stress has units of pascals (Pa), same as pressure, since both are force over area. A thicker sample spreads the same force over more material, so experiences less force per unit area.

Tensile strain

Tensile strain is the extension produced per unit original length:

$\varepsilon = \dfrac{\Delta L}{L}$

where $\varepsilon$ is strain, $\Delta L$ is the extension, and $L$ is the original length. Being a ratio of two lengths, strain has no units — often quoted as a percentage. A longer sample stretches further in absolute terms for the same proportional deformation.

Stress and strain both divide out sample dimensions, leaving quantities that depend only on the material — exactly what's needed to compare materials on equal footing.

The Young modulus

For a material behaving elastically, stress and strain are directly proportional, and their ratio is a constant that depends only on the material — the Young modulus, $E$.

DerivationE = FL / (AΔL), from stress over strain
1
The Young modulus is defined as the ratio of tensile stress to tensile strain: $E = \dfrac{\sigma}{\varepsilon}$.
2
Substitute the definitions $\sigma = \dfrac{F}{A}$ and $\varepsilon = \dfrac{\Delta L}{L}$: $E = \dfrac{F/A}{\Delta L/L}$.
3
Dividing by a fraction is the same as multiplying by its reciprocal: $E = \dfrac{F}{A}\times\dfrac{L}{\Delta L} = \dfrac{FL}{A\,\Delta L}$.
4
Since strain $\varepsilon$ has no units, $E$ has the same units as stress: pascals (Pa).
Dividing something in Pa by a dimensionless number leaves it in Pa.
▪ derived

Because $E$ is a ratio of quantities with sample geometry already divided out, it's a genuine material property — the same whether you test a short thick sample or a long thin one, within their elastic limits. A large Young modulus means a stiff material needing large stress for a given strain. Steel's is around 200 GPa, against roughly 0.01–0.1 GPa for rubber — a difference of several thousand times.

Required Practical: Determination of the Young Modulus

AQA Required Practical

This is AQA's Required Practical 4: determining the Young modulus of a wire.

Equipment

EquipmentPurpose
Test wire (e.g. copper, known gauge)The sample whose Young modulus is being measured
Control wire (same material, unloaded)Cancels out thermal expansion/sag, since it experiences the same conditions as the test wire without the load
Two G-clampsFix both wires securely to the bench edge
Marker + fixed scale (or vernier scale/travelling microscope)Measures the small extension of the test wire relative to the control wire
Micrometer screw gaugeMeasures the wire's diameter, to calculate cross-sectional area
Metre ruleMeasures the wire's original length
Mass hanger + slotted massesApplies a series of known increasing loads
Safety gogglesProtects against a wire snapping under tension
Protective floor mat/sandbagCushions a falling mass if the wire does snap

Method

MethodStress-strain graph from a loaded wire
1
Clamp the test wire and an identical, unloaded control wire side by side at a bench edge, running parallel to a fixed scale. Apply a small initial load to the test wire to remove any kinks before starting.
2
Measure the test wire's original length $L$ (from the clamp to the reference marker) with a metre rule.
3
Measure the wire's diameter with the micrometer at several points along its length, and at two angles at right angles at each point; average the readings, then calculate cross-sectional area $A=\pi d^2/4$.
4
Attach a marker to the test wire aligned against the fixed scale, using the control wire's own marker as a zero reference, and record the starting position.
5
Add a small increment of mass to the hanger, let the wire settle, and record the new marker position relative to the control wire — the difference gives the extension $\Delta L$.
6
Repeat step 5 for a sequence of increasing loads, staying well within the wire's elastic limit throughout.
7
Calculate stress $\sigma=F/A$ and strain $\varepsilon=\Delta L/L$ for each loading, then plot stress against strain.
8
Provided the limit of proportionality isn't exceeded, the plot is a straight line through the origin — the gradient of that line is the Young modulus $E$.
▪ method

Sources of error and how to minimise them

Thermal expansion mistaken for real extension

Room-temperature changes make a wire expand or contract slightly, which could be wrongly read as extension due to loading. Measure the test wire's extension relative to the unloaded control wire (mounted on the same support, experiencing the same conditions) rather than against a fixed external scale, so thermal effects cancel out.

Exceeding the elastic limit invalidates later readings

Loading the wire beyond its elastic limit — even briefly, on a single trial — leaves permanent extension behind, so every subsequent "unloaded" length is wrong and the whole set of repeats is contaminated. Stay well within the known elastic limit throughout, and check the wire returns to its original length once all load is removed at the end.

Non-uniform wire diameter

A drawn wire is rarely perfectly uniform in cross-section. Measure the diameter at several points along the wire, and at two right angles at each point, then average — using a single measurement risks a biased area value.

Parallax error reading the scale

Reading the marker position from an angle introduces error. View the marker at eye level, or use a vernier scale/travelling microscope for greater precision on the small extensions involved.

Safety: a taut wire under load can snap

Wear eye protection throughout, and stand to the side of the wire rather than directly in front of or behind it, since a snapped wire under tension can whip back sharply.

Key takeaways

  • Hooke's law: $F = k\Delta L$, with $k$ the stiffness of a particular sample (N m−1), valid up to the limit of proportionality.
  • The limit of proportionality (graph stops being straight) and the elastic limit (deformation becomes permanent beyond this point) are different points — a material can be non-linear yet still fully elastic between them.
  • Tensile stress $\sigma = F/A$ (Pa) and tensile strain $\varepsilon = \Delta L/L$ (no units) strip out sample geometry, leaving quantities that describe the material itself.
  • The Young modulus $E = \sigma/\varepsilon = \dfrac{FL}{A\,\Delta L}$, measured in pascals, is a genuine material property, independent of a sample's length or cross-sectional area.
  • A larger Young modulus means a stiffer material, requiring more stress to produce the same strain — steel's is several thousand times rubber's.
  • The Young modulus is measured experimentally as the gradient of a stress-strain graph for a loaded wire, using a control wire to correct for thermal effects, with repeats kept well within the elastic limit.