Physics/Lessons/Electric Circuits/Series & Parallel Circuits
Physics · Electric Circuits · AS Level

Series & Parallel Circuits

Two resistors can be wired together in only two fundamentally different ways — one after another, or side by side — and those arrangements behave completely differently. This lesson builds the maths behind both from first principles.

10 min read

Two ways to connect a circuit

Take three resistors and a battery. There are only two sensible ways to wire them up. Chain them one after another so charge passes through the first, then the second, then the third, with no other route — a series connection. Or give each resistor its own branch between the same two points, so charge splits up and takes whichever path it likes — a parallel connection. Real circuits are usually a mixture of both, but you need to understand each piece separately first.

Each arrangement imposes a different constraint on current and voltage, and those constraints are what let us derive a formula for total resistance in each case.

A simple circuit diagram showing a single loop with a cell/battery symbol on the left-hand side connected by wires to three resistor symbols (zig-zag rectangles) drawn one after another in a single chain around the loop, labelled R1, R2 and R3, with a single ammeter symbol (a circle with the letter A inside) placed in the wire of the loop showing that the same current flows through the cell and all three resistors in turn.
Three resistors connected in series: one continuous loop, one path for the current, one ammeter reading for the whole circuit.

Resistors in series

Picture the three resistors wired in a single loop with the cell. Because there's only one path for charge, whatever current flows out of the cell flows through every resistor — there's nowhere else to go. So the current $I$ is the same everywhere in a series circuit.

The second fact comes from energy conservation: as a charge travels round the loop and back to where it started, all the energy it picked up from the cell must be used up along the way, shared among the resistors it passed through. So the total potential difference equals the sum of the individual potential differences.

DerivationTotal resistance in series, R = R₁ + R₂ + R₃
1
The same current $I$ flows through every resistor in the chain.
Charge has no alternative route — it's a single loop.
2
The total potential difference splits across the resistors: $V_{total} = V_1 + V_2 + V_3$.
Energy conservation around the loop — every joule supplied by the cell is transferred somewhere.
3
Write each pd using $V=IR$: $V_1 = IR_1$, $V_2 = IR_2$, $V_3 = IR_3$.
Same current $I$ in each, because it's the one current flowing round the whole loop.
4
Substitute into the sum: $IR_{total} = IR_1 + IR_2 + IR_3$.
The left-hand side is just the total pd written as (total resistance) × (current).
5
Divide both sides by the common factor $I$: $R_{total} = R_1 + R_2 + R_3$.
This generalises to any number of resistors in series — just keep adding terms.
▪ derived

This result is physical, not just mathematical: adding another resistor in series can only ever increase total resistance — more material for charge to fight through, no alternative route to relieve the pressure.

A simple circuit diagram showing a cell/battery symbol connected to three resistors R1, R2 and R3 drawn as three separate horizontal branches stacked one above another, each branch running between the same two shared vertical junction wires (one junction point on the left connecting to the positive terminal of the cell, one junction point on the right connecting back to the negative terminal), so that each resistor forms its own independent parallel path between the identical pair of junction points.
Three resistors connected in parallel: three separate branches, each spanning the same two junctions, each carrying its own share of the current.

Resistors in parallel

Now spread the same three resistors into separate branches, each connected between the same two junction points. Because both ends of every resistor are tied to the same two points, each sees exactly the same potential difference. So the potential difference $V$ is the same across every branch.

The second fact is charge conservation at a junction: whatever current arrives has to leave again, so it splits among the branches on the way out and recombines to the same total on the way back. The total current supplied by the cell is the sum of the branch currents.

DerivationTotal resistance in parallel, 1/R = 1/R₁ + 1/R₂ + 1/R₃
1
The same potential difference $V$ is across every resistor.
All three branches connect the same two points, so they all experience the same voltage.
2
The total current is the sum of the branch currents: $I_{total} = I_1 + I_2 + I_3$.
Conservation of charge at the junctions — current in equals current out.
3
Write each current using $I = V/R$: $I_1 = V/R_1$, $I_2 = V/R_2$, $I_3 = V/R_3$.
Same voltage $V$ across each, from step 1.
4
Substitute into the sum: $\dfrac{V}{R_{total}} = \dfrac{V}{R_1} + \dfrac{V}{R_2} + \dfrac{V}{R_3}$.
The left-hand side is the total current written as (total voltage) ÷ (total resistance).
5
Divide both sides by the common factor $V$: $\dfrac{1}{R_{total}} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3}$.
Again this generalises — add one reciprocal term per resistor, for any number of parallel branches.
▪ derived

Notice the shape of the result is the mirror image of the series case — reciprocals instead of the resistances themselves. Physically, adding another parallel branch gives charge another route to escape by, so total resistance always goes down when you add a resistor in parallel, never up. This is why plugging more appliances into the same socket circuit increases the current drawn from the wall — each appliance is another parallel branch, lowering the overall resistance the supply sees.

The underlying principles

Everything above comes down to two conservation laws that hold in any dc circuit. Conservation of charge means current into any junction equals current out, and current is the same at every point around a loop with no junctions. Conservation of energy means that, round any complete loop, the total energy supplied per unit charge (sum of the emfs) equals the total energy transferred per unit charge (sum of the potential drops). Series and parallel formulas are just these two laws worked through for two particular arrangements.

These have their own names: Kirchhoff's first law is the charge-conservation statement — current in equals current out at a junction — and Kirchhoff's second law is the energy-conservation statement around a closed loop.

Power in a circuit

Current tells you how much charge flows per second; potential difference tells you how much energy each coulomb transfers as it passes through a component. Multiply them and you get energy transferred per second — power. Over a time $t$, total energy transferred is $E = IVt$, and the rate of transfer is $P = IV$.

Because $V$, $I$ and $R$ are linked by $V=IR$ for a resistor, the power equation can be rewritten in two other useful forms.

DerivationP = IV, P = I²R and P = V²/R are all the same equation
1
Start from the basic power relationship, $P = IV$.
Power is energy transferred per second; $V$ is energy transferred per unit charge; $I$ is charge per second.
2
For a resistor, $V = IR$. Substitute this in place of $V$: $P = I \times (IR) = I^2R$.
Useful when you know the current through a resistor and its resistance, but not the voltage across it.
3
Alternatively substitute $I = V/R$ in place of $I$: $P = \left(\dfrac{V}{R}\right) \times V = \dfrac{V^2}{R}$.
Useful when you know the voltage across a resistor and its resistance, but not the current.
4
All three — $P=IV$, $P=I^2R$, $P=V^2/R$ — describe exactly the same physical quantity; the choice between them is just whichever two variables you happen to know.
▪ derived

Cells in series and parallel

The same series/parallel thinking applies to cells, not just resistors. Connect identical cells in series, positive terminal to negative terminal, and their emfs add — two 1.5 V cells in series drive a circuit with a combined emf of 3 V, since each charge passing through picks up energy from both cells in turn.

Connect identical cells in parallel instead, and the combined emf stays the same as a single cell, but the arrangement can now supply more current, or supply the same current for longer, since the total charge delivered is shared between the cells rather than coming from one. This is the parallel-branch idea from earlier, applied to sources of emf instead of resistors.

Key takeaways

  • In series, resistors share the same current, and their potential differences add — giving $R_{total} = R_1 + R_2 + R_3 + \ldots$, which always increases as you add resistors.
  • In parallel, resistors share the same potential difference, and their currents add — giving $\dfrac{1}{R_{total}} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} + \ldots$, which always decreases as you add resistors.
  • Both derivations rest on the same two ideas: conservation of charge (current in equals current out at a junction) and conservation of energy (potential difference measures energy transferred per unit charge) — also known as Kirchhoff's first and second laws respectively.
  • Power delivered to a resistor can be written as $P=IV$, $P=I^2R$ or $P=V^2/R$ — three forms of the same relationship, related by substituting $V=IR$ or $I=V/R$.
  • Energy transferred over a time $t$ is $E = IVt$ — power is just this rate of energy transfer.
  • Identical cells in series add their emfs together; identical cells in parallel keep the same combined emf but can supply more current, or supply it for longer.