Physics/Option Modules/Astrophysics/Stefan–Boltzmann Law
Physics · Astrophysics · A2 Level

Stefan–Boltzmann Law

Wien's law gives you a star's temperature. But two stars can share exactly the same surface temperature and still pump out wildly different amounts of power — because one is simply far bigger than the other. The missing piece is a law connecting temperature, size and total power output all in one equation.

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Stating Stefan's law

The Stefan–Boltzmann law (often just called Stefan's law) gives the total power radiated by a black body in terms of its surface area and temperature:

$$P = \sigma A T^4$$

where $P$ is the total power radiated (in watts), $A$ is the surface area of the radiating body (in $\text{m}^2$), $T$ is its surface temperature (in kelvin), and $\sigma$ is the Stefan–Boltzmann constant, a fixed number with the same value for every black body. Notice the very strong dependence on temperature: because power depends on $T^4$, even a modest increase in temperature produces a dramatic increase in radiated power — doubling a star's surface temperature increases its power output sixteen-fold, assuming its size stays the same.

Applying the law to a star

Stars are, to a very good approximation, spheres, so the general law above is normally applied to stars using the surface area of a sphere of radius $r$:

$$A = 4\pi r^2$$

Substituting this into Stefan's law gives the form of the equation used throughout stellar astrophysics:

$$P = 4\pi r^2 \sigma T^4$$

Here $P$ is usually identified with the star's luminosity $L$ from the earlier lesson on the inverse square law, since luminosity is exactly the total power radiated by the star. This version of the law — with the $4\pi r^2$ spelled out explicitly — is the one you should reach for whenever a question gives you (or asks you to find) a star's radius.

Linking luminosity, temperature and radius

Stefan's law, combined with Wien's law and the inverse square law from the previous lessons, gives astronomers a genuinely powerful toolkit. Between the three relationships, any one of a star's luminosity, surface temperature, or radius can be found if the other two are known:

  • Wien's law gives temperature from the peak wavelength of the spectrum.
  • The inverse square law gives luminosity from measured flux and known distance.
  • Stefan's law then links luminosity, temperature and radius together, so knowing any two lets you find the third.

This three-way relationship between $L$, $T$ and $r$ is central to how stars are compared and classified. For example, two stars with the same luminosity but different surface temperatures cannot be the same size: the cooler star must have a much larger radius to make up, through sheer surface area, for radiating less power per square metre than the hotter one. This exact idea — using $L$ and $T$ together to infer relative sizes — is exactly what makes sense of the giant and dwarf regions of the Hertzsprung–Russell diagram, covered in the next lesson.

Worked exampleFinding a star's radius from L and T
1
A star has luminosity $L = 3.0\times10^{27}\ \text{W}$ and surface temperature $T = 5800\ \text{K}$. Take $\sigma = 5.67\times10^{-8}\ \text{W m}^{-2}\text{K}^{-4}$. Find the star's radius.
Start from $L = 4\pi r^2 \sigma T^4$ and rearrange to make $r$ the subject.
2
$r^2 = \dfrac{L}{4\pi \sigma T^4}$
Divide both sides by $4\pi\sigma T^4$.
3
$T^4 = 5800^4 \approx 1.13\times10^{15}\ \text{K}^4$
Evaluate the temperature term first, since it's raised to a high power.
4
$r^2 = \dfrac{3.0\times10^{27}}{4\pi \times 5.67\times10^{-8} \times 1.13\times10^{15}} \approx 3.75\times10^{17}\ \text{m}^2$
Substitute all values into the rearranged equation.
5
$r = \sqrt{3.75\times10^{17}} \approx 6.1\times10^{8}\ \text{m}$
Take the square root — this is close to the Sun's actual radius of about $7\times10^8\ \text{m}$, a useful sanity check.
r ≈ 6.1 × 10⁸ m
The key idea

Luminosity, temperature and radius are not three independent pieces of information about a star — Stefan's law locks them together. Given any two, the third is fixed. This is the essential piece of physics behind reading a star's size directly off its position on the Hertzsprung–Russell diagram, which plots exactly the other two quantities: luminosity and temperature.

Key takeaways

  • Stefan's law, $P = \sigma A T^4$, gives the total power radiated by a black body from its surface area and surface temperature.
  • For a spherical star of radius $r$, this becomes $P = 4\pi r^2 \sigma T^4$, using the surface area of a sphere, $A = 4\pi r^2$.
  • Radiated power depends on the fourth power of temperature, so small temperature changes produce large changes in power output.
  • Combining Stefan's law with Wien's law and the inverse square law lets any one of a star's luminosity, temperature or radius be found from the other two.
  • Two stars of equal luminosity but different temperatures must have different radii — the cooler one must be larger to radiate the same total power.
  • This three-way relationship between luminosity, temperature and radius underpins the structure of the Hertzsprung–Russell diagram, covered next.