Mathematics/Lessons/Trigonometry/Radians and Arc Length
Pure · Trigonometry · Year 2

Radians and Arc Length

A radian isn't an arbitrary unit — it's the angle a circle's own radius carves out of its circumference, and it's what makes the formula for an arc's length remarkably simple.

7 min read 4 worked examples

Defining the radian

So far, angles have been measured in degrees, where a full turn is split into $360$ equal parts. But there's a second, more natural unit: the radian. One radian is defined as the angle subtended at the centre of a circle by an arc whose length equals the circle's radius.

A circle centred at O. A radius r is drawn to a point on the circle, and a second radius is drawn to a nearby point on the circle so that the arc between them, along the circle's edge, is exactly equal in length to the radius r. The angle at O between the two radii is marked and labelled 1 rad.
When the arc cut off equals the radius r in length, the angle at the centre is defined to be 1 radian (≈ 57.3°).

Since the full circumference of a circle is $2\pi r$ — that is, $2\pi$ "radius-lengths" — a complete turn measures exactly $2\pi$ radians. This gives the fundamental conversion:

$\pi \text{ radians} = 180°$

From this, converting between the two units is just scaling: multiply a degree value by $\dfrac{\pi}{180}$ to get radians, or multiply a radian value by $\dfrac{180}{\pi}$ to get degrees. Radians are often left in exact form as multiples of $\pi$, which is why the common angles from Year 1 reappear here in a new guise:

$30° = \dfrac{\pi}{6} \quad 45° = \dfrac{\pi}{4} \quad 60° = \dfrac{\pi}{3} \quad 90° = \dfrac{\pi}{2} \quad 180° = \pi \quad 360° = 2\pi$
Same exact values, new unit

All the exact trig values memorised in Year 1 — $\sin\dfrac{\pi}{6}=\dfrac12$, $\cos\dfrac{\pi}{4}=\dfrac{1}{\sqrt2}$, $\tan\dfrac{\pi}{3}=\sqrt3$, and so on — carry over unchanged. Only the label on the angle has changed from degrees to radians; the geometry, and therefore the ratio, is identical.

Arc length

For a circle of radius $r$, an arc subtending an angle $\theta$ measured in radians at the centre has length:

$s = r\theta$
DerivationArc length as a proportion of the circumference
1
The full circumference of a circle of radius $r$ is $2\pi r$, corresponding to the full angle $2\pi$ radians.
Standard circumference formula, and a complete turn is $2\pi$ radians.
2
An arc subtending angle $\theta$ is the same proportion of the full circumference as $\theta$ is of the full turn: $\dfrac{s}{2\pi r} = \dfrac{\theta}{2\pi}$.
Arc length scales directly with the angle it subtends.
3
Multiply both sides by $2\pi r$: $s = 2\pi r \cdot \dfrac{\theta}{2\pi} = r\theta$.
The $2\pi$ cancels, leaving a remarkably simple formula.
▪ QED
Radians are non-negotiable here

$s=r\theta$ is only valid when $\theta$ is measured in radians. Using a degree value directly gives a wrong answer by a factor of $\dfrac{\pi}{180}$ — always convert first if an angle is given in degrees. The next lesson builds on this same idea to find the area of a sector.

Worked example 1

Converting between degrees and radians
Convert (a) $150°$ to radians in terms of $\pi$, and (b) $\dfrac{5\pi}{4}$ radians to degrees.
MethodMultiply by the appropriate conversion factor
1
(a) Multiply by $\dfrac{\pi}{180}$: $150 \times \dfrac{\pi}{180} = \dfrac{150\pi}{180} = \dfrac{5\pi}{6}$.
Degrees to radians uses the factor π/180.
2
So $150° = \dfrac{5\pi}{6}$ radians.
Simplified exact answer.
3
(b) Multiply by $\dfrac{180}{\pi}$: $\dfrac{5\pi}{4} \times \dfrac{180}{\pi} = \dfrac{5 \times 180}{4} = 225$.
Radians to degrees uses the factor 180/π; the π cancels.
4
So $\dfrac{5\pi}{4}$ radians $= 225°$.
Final answer.
▪ solved
Quick check

$\pi$ radians $=180°$, so $\dfrac{5\pi}{4}$ is a bit more than $\pi$ (i.e. more than a straight line, $180°$), consistent with an answer of $225°$.

Worked example 2

Arc length
A circle has radius $8\text{ cm}$. Find the length of the arc subtending an angle of $\dfrac{2\pi}{3}$ radians at the centre.
MethodApply $s=r\theta$ directly, since $\theta$ is already in radians
1
$r = 8$, $\theta = \dfrac{2\pi}{3}$, both ready to substitute.
θ is already in radians, so no conversion is needed.
2
$s = r\theta = 8 \times \dfrac{2\pi}{3} = \dfrac{16\pi}{3}$.
Substitute directly into the arc length formula.
3
$s = \dfrac{16\pi}{3} \approx 16.8\text{ cm}$ (3 s.f.).
Exact form and decimal approximation.
▪ solved

Worked example 3

Finding the angle from an arc length
An arc of a circle of radius $5\text{ cm}$ has length $22\text{ cm}$. Find the angle subtended at the centre, in radians and in degrees.
MethodRearrange $s=r\theta$ for $\theta$, then convert
1
$\theta = \dfrac{s}{r} = \dfrac{22}{5} = 4.4$ radians.
Divide the arc length by the radius.
2
$\theta = 4.4 \times \dfrac{180}{\pi} \approx 252.1°$ (1 d.p.).
Convert to degrees using the standard factor.
▪ solved
Sanity check

$4.4$ radians is more than $\pi\approx3.14$ (a straight line, $180°$) but less than $2\pi\approx6.28$ (a full turn), so the angle should land somewhere between $180°$ and $360°$ — and $252.1°$ does exactly that. This is a reflex angle, which is perfectly valid for an arc subtending more than half the circle.

Worked example 4

Perimeter of a sector · Challenge
A sector $OAB$ has radius $6\text{ cm}$ and angle $\theta = \dfrac{\pi}{5}$ radians. Find the exact perimeter of the sector.
MethodCombine two straight radii with the curved arc length
1
The perimeter of a sector is made of two straight radii $OA$, $OB$, plus the curved arc $AB$: perimeter $= 2r + s$.
A sector's boundary has two straight edges and one curved edge.
2
Arc length: $s = r\theta = 6 \times \dfrac{\pi}{5} = \dfrac{6\pi}{5}$.
Apply the arc length formula with θ in radians.
3
Perimeter $= 2(6) + \dfrac{6\pi}{5} = 12 + \dfrac{6\pi}{5}$ cm (exact).
Add the two radii to the arc length; leave in exact π form as requested.
▪ solved
Look deeper — a sector isn't just an arc

A common slip is to give the arc length $\dfrac{6\pi}{5}$ alone as "the perimeter" — but a sector's boundary has two straight radii as well as the curved edge. Always sketch the sector and count all three sides of its boundary before adding.

Common mistake

Plugging a degree value straight into $s=r\theta$ without converting to radians first — this silently multiplies the correct answer by a factor of roughly $57.3$ (since $1$ radian $\approx 57.3°$). Always check the angle's units before substituting, and convert with $\times\frac{\pi}{180}$ if it's given in degrees.

Check yourself

A sector has radius $7\text{ cm}$ and perimeter $25\text{ cm}$. Find the angle $\theta$ in radians, and hence the area of the sector.
(Hint: perimeter $=2r+r\theta$ — rearrange for $\theta$ first, then use $A=\frac12r^2\theta$ for the area.)

Method
1
Perimeter $= 2r+r\theta = 2(7)+7\theta = 14+7\theta$, so $25=14+7\theta$.
Write the perimeter in terms of r and θ, then substitute the given values.
2
$7\theta = 11 \Rightarrow \theta = \dfrac{11}{7} \approx 1.571$ radians.
Isolate θ.
3
$A = \dfrac{1}{2}r^2\theta = \dfrac{1}{2}(7)^2\left(\dfrac{11}{7}\right) = \dfrac{1}{2}(49)\left(\dfrac{11}{7}\right) = 38.5\text{ cm}^2$.
Substitute r and the found θ into the sector area formula from the next lesson.
4
$\theta = \dfrac{11}{7}$ radians and $A = 38.5\text{ cm}^2$.
Final answers.
▪ solved