Pure · Trigonometric Identities and Equations · Year 1

Angles in All Four Quadrants

The unit circle splits into four quadrants, and in each one a different combination of sin, cos and tan is positive — the CAST diagram turns that pattern into a single picture you can read off in seconds.

9 min read 4 worked examples

Four quadrants, four sign patterns

The unit circle splits naturally into four quadrants, numbered anticlockwise from the positive $x$-axis: 1st ($0°$–$90°$), 2nd ($90°$–$180°$), 3rd ($180°$–$270°$), 4th ($270°$–$360°$). Since a point on the circle at angle $\theta$ has coordinates $(\cos\theta, \sin\theta)$, the signs of $\sin\theta$ and $\cos\theta$ are just the signs of that point's $y$- and $x$-coordinates — and those flip as the point moves from quadrant to quadrant.

Reading the signs off the circle

1st quadrant: $x>0, y>0$, so $\sin,\cos$ both positive (and $\tan=\sin/\cos$ positive too). 2nd quadrant: $x<0, y>0$, so only $\sin$ is positive. 3rd quadrant: $x<0, y<0$, so both are negative — but $\tan = \sin/\cos$ is a negative divided by a negative, which is positive. 4th quadrant: $x>0, y<0$, so only $\cos$ is positive.

The CAST diagram

That pattern is exactly what the CAST diagram summarises: label the four quadrants, anticlockwise starting from the 4th, with the letters C, A, S, T — each letter marking which ratios are positive in that quadrant.

4th quadrant — C: only Cosine is positive.
1st quadrant — A: All three ratios are positive.
2nd quadrant — S: only Sine is positive.
3rd quadrant — T: only Tangent is positive.

Everywhere a letter doesn't appear, that ratio is negative. "CAST", read anticlockwise starting just below the $x$-axis, is simply a mnemonic for the sign pattern the circle already gives you.

A circle divided into four quadrants by the x and y axes, labelled anticlockwise from the 4th quadrant: C (cosine positive) in the bottom-right, A (all ratios positive) in the top-right, S (sine positive) in the top-left, T (tangent positive) in the bottom-left.
The CAST diagram: reading anticlockwise from the 4th quadrant gives C, A, S, T — the ratio that's positive in each quadrant.

Reference angles

The other half of the picture is the reference angle: the acute angle between the radius and the (nearest) $x$-axis. Every angle's ratio has the same size as its reference angle's ratio — only the sign, decided by CAST, can differ.

Finding the reference angle

1st quadrant: reference angle $=\theta$ itself. 2nd quadrant: reference angle $=180°-\theta$. 3rd quadrant: reference angle $=\theta-180°$. 4th quadrant: reference angle $=360°-\theta$. In every case, it's the acute "distance" from $\theta$ back to the nearest end of the $x$-axis.

Worked example 1

Sign and quadrant from an angle
State the quadrant, the reference angle, and the sign of $\cos 200°$.
MethodLocate the quadrant, then apply CAST
1
$200°$ lies between $180°$ and $270°$, so it's in the 3rd quadrant.
Compare to the four quadrant boundaries.
2
Reference angle $= 200° - 180° = 20°$.
3rd-quadrant rule.
3
In the 3rd quadrant (T), only tan is positive — so cosine is negative here.
Read CAST for this quadrant.
4
So $\cos 200° = -\cos 20°$.
Same size as the reference angle, sign from CAST.
▪ solved
Examiner's eye

Two separate questions, two separate steps: which acute angle gives the same size (the reference angle), and what sign does this quadrant give that ratio (CAST). Keeping them apart avoids the common slip of getting the right number with the wrong sign.

Worked example 2

Exact value via CAST · no calculator
Find the exact value of $\sin 150°$ and $\tan 315°$.
MethodReference angle from the known exact values, sign from CAST
1
$150°$ is in the 2nd quadrant (S): reference angle $=180°-150°=30°$, and sine is positive here.
2nd-quadrant rule, sine positive.
2
$\sin 150° = \sin 30° = \dfrac12$.
Exact value of 30°, unchanged in sign.
3
$315°$ is in the 4th quadrant (C): reference angle $=360°-315°=45°$, and tan is negative here (only cosine is positive in the 4th quadrant).
4th-quadrant rule, tan negative.
4
$\tan 315° = -\tan 45° = -1$.
Exact value of 45°, sign flipped.
▪ solved
The key insight

CAST and reference angles turn every angle's exact trig value into one of the handful you already know for $30°, 45°, 60°$ — you're never actually evaluating a new ratio, just relocating a familiar one and fixing its sign.

Worked example 3

Using CAST to select the right quadrant
Given that $\cos\theta = -0.6$ and $180° \le \theta \le 360°$, find $\theta$ to 1 d.p.

Normally a negative cosine gives two candidate quadrants (2nd and 3rd) — but the given range rules one of them out before you even start.

MethodFind the reference angle, then place it in the correct quadrant
1
Ignore the sign for a moment: $\cos^{-1}(0.6) = 53.1°$ — this is the reference angle.
Work with the size first.
2
Cosine is negative in the 2nd and 3rd quadrants. The given range $180°$–$360°$ covers the 3rd and 4th quadrants — so only the 3rd quadrant (T) is consistent with both the sign and the range.
Intersect "where cos is negative" with the given range.
3
3rd-quadrant angle with reference angle $53.1°$: $\theta = 180° + 53.1° = 233.1°$.
3rd-quadrant rule, rearranged.
▪ solved
Common mistake

Don't just take $\cos^{-1}(-0.6)$ on the calculator and stop — it returns $126.9°$, the 2nd-quadrant solution, which falls outside the given range here. Always find the reference angle from the positive version of the ratio, then use CAST and the given range together to place it in the correct quadrant(s).

Worked example 4

All solutions from one reference angle · Challenge
Given that $\tan 35° = 0.700$ (3 s.f.), find all values of $\theta$ in $0° \le \theta \le 360°$ for which $\tan\theta = -0.700$.
MethodReference angle 35°, placed in every quadrant where tan is negative
1
Reference angle: $35°$ (from the given value, ignoring sign).
Same size, sign handled separately.
2
Tan is negative in the 2nd quadrant (S) and the 4th quadrant (C) — the two quadrants CAST doesn't mark with a T.
Read off CAST for "tan negative".
3
2nd quadrant: $\theta = 180° - 35° = 145°$.
2nd-quadrant rule.
4
4th quadrant: $\theta = 360° - 35° = 325°$.
4th-quadrant rule.
5
Solutions: $\theta = 145°$ and $\theta = 325°$.
Both quadrants where tan is negative, within range.
▪ solved
Look deeper — this is the CAST-diagram version of solving a trig equation

This is exactly the method the next lesson formalises into a general procedure for solving trig equations: find the reference angle from the size of the given ratio, use CAST to identify every quadrant with the right sign, then place the reference angle in each one using the four quadrant rules. Two negative-tan quadrants means two solutions — never fewer, never more, within one $360°$ cycle.

Common mistake

The reference angle is always taken from the acute, positive version of the ratio — never plug a negative value straight into $\sin^{-1}$, $\cos^{-1}$ or $\tan^{-1}$ and expect the calculator's output to already be the reference angle you need; check what quadrant it's actually landed you in first.

Check yourself

State the quadrant, reference angle, and exact value of $\sin 240°$.
(Hint: 240° is between 180° and 270°.)

Method
1
$240°$ is between $180°$ and $270°$: the 3rd quadrant (T).
2
Reference angle $= 240° - 180° = 60°$.
3
In the 3rd quadrant, only tan is positive, so sine is negative here.
4
$\sin 240° = -\sin 60° = -\dfrac{\sqrt3}{2}$.
▪ solved